Answer :


Clearly, |x–2|–2≠0


|x–2|≠2


x≠0 and x≠4


Now, 2 case arise:


Case 1:–∞ <x<2


For this, |x–2|=–(x–2)





x ϵ (0,1] …(1)


Case 2: 2<x<∞


For this, |x–2|=x–2




x ϵ [3,4) …(2)


x ϵ (0,1] [3, 4) (from 1 and 2)


We can verify the answers using graph as well.



Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Solve each of theRD Sharma - Mathematics

A solution is to RD Sharma - Mathematics

A company manufacRD Sharma - Mathematics

<span lang="EN-USRS Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal - Mathematics

Solve each of theRS Aggarwal - Mathematics

Solve x + 5 > RS Aggarwal - Mathematics

Find the solutionRS Aggarwal - Mathematics

If |x – 1| > 5Mathematics - Exemplar