Answer :

All the given numbers are divisible by 7

From divisibility rules we have (2a + 3b + c)

(a) 427 is divisible by 7

Since, (2(4) + 3(2) + 7) = 8 + 6 + 7 = 21 is divisible by 7

(b) 3514 is divisible by 7

Since, (6(3) + 2(5) + 3(1) + 4) = 18 + 10 + 3 + 4 = 35 is divisible by 7

(c) 861 is divisible by 7

Since, (2(8) + 3(6) + 1) = 16 + 18 + 1 = 35 is divisible by 7

(d) 4676 is divisible by 7

Since, (6(4) + 2(6) + 3(7) + 6) = 24 + 12 + 21 + 6 = 63 is divisible by 7

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