Answer :

Radius of the circle = 14cm

Angle subtend at center = 90°

By Pythagoras theorem = AB^{2} = OA^{2} + OB^{2}

= 14^{2} +14^{2}

Area of sector OAB =

=

=

Area of triangle AOB =

So area of minor segment – OACB =area of sector – area of triangle

= 154 – 98 = 56cm^{2}

Area of major segment = area of circle - area of minor segment

= 44×14 – 56 = 560cm^{2}

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