Q. 3

A chord of a circle of radius 14cm makes a right angle at the centre. Find the areas of the minor and major segments of the circle.

Answer :

Radius of the circle = 14cm

Angle subtend at center = 90°

By Pythagoras theorem = AB2 = OA2 + OB2

= 142 +142

Area of sector OAB =



Area of triangle AOB =

So area of minor segment – OACB =area of sector – area of triangle

= 154 – 98 = 56cm2

Area of major segment = area of circle - area of minor segment

= 44×14 – 56 = 560cm2

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