Answer :

Since,

A diagonal of parallelogram divides it into two triangles of equal area


Therefore,


Area ( = Area ()


Area ( + Area of parallelogram DLOP + Area ()


Area ( + Area of parallelogram DLOP + Area ( (i)


Since,


AO and CO are diagonals of parallelograms AMOP and OQCL respectively


Therefore,


Area ( = Area ( (ii)


Area ( = Area ( (iii)


Subtracting (ii) from (iii), we get


Area of parallelogram DLOP = Area of parallelogram BMOQ.


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