In Fig. 15.89, AB

Since,

A diagonal of parallelogram divides it into two triangles of equal area

Therefore,

Area ( = Area ( )

Area ( + Area of parallelogram DLOP + Area ( )

Area ( + Area of parallelogram DLOP + Area ( (i)

Since,

AO and CO are diagonals of parallelograms AMOP and OQCL respectively

Therefore,

Area ( = Area ( (ii)

Area ( = Area ( (iii)

Subtracting (ii) from (iii), we get

Area of parallelogram DLOP = Area of parallelogram BMOQ.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

In Q. No. 1, if ARD Sharma - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

ABCD is a paralleRD Sharma - Mathematics

In Δ ABC, ERD Sharma - Mathematics

P is the mid-poinRD Sharma - Mathematics

Diagonals of a quRD Sharma - Mathematics

ABCD is a trapeziRD Sharma - Mathematics