Answer :

Since,

A diagonal of parallelogram divides it into two triangles of equal area

Therefore,

Area ( = Area ()

Area ( + Area of parallelogram DLOP + Area ()

Area ( + Area of parallelogram DLOP + Area ( (i)

Since,

AO and CO are diagonals of parallelograms AMOP and OQCL respectively

Therefore,

Area ( = Area ( (ii)

Area ( = Area ( (iii)

Subtracting (ii) from (iii), we get

Area of parallelogram DLOP = Area of parallelogram BMOQ.

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