Q. 24.2( 19 Votes )

# A field is in the

Answer :

Let us consider a parallelogram **ABCD**,

We know that the lengths of opposite sides of a parallelogram are equal.

i.e, **AD = BC** ...... (1)

**AB = CD** ...... (2)

We also know that Perimeter of Parallelogram is the sum of the lengths of its sides.

i.e, Perimeter of Parallelogram(P) = **AB + BC + CD + DA** - - (3)

According to the problem it is given that,

The perimeter of Parallelogram(**P**) is 450m and

One side is 75m larger than the other side.

Let us consider the length of smaller be ‘**x**’m

Then from the figure,

**BC = AD = x**m ...... - - (4)

Then, **AB = CD = (x + 75)**m ...... (5)

From eq(1),

⇒ x + x + 75 + x + x + 75 = 450 (since **P** = 450m)

⇒ 4x + 150 = 450

⇒ 4x = 450 - 150

⇒ 4x = 300

⇒

⇒ **x = 75**m.

From Eq(4) we can say that,

**BC = DA = 75**m.

**AB = CD = (75 + 75) = 150**m.

The lengths of sides **AB, BC, CD** and **DA** is **150**m, **75**m, **150**m, **75**m.

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