Answer :
In ΔPOA and 
QOC, we have
∠AOP = ∠COQ (Vertically opposite angle)
OA = OC (Diagonals of parallelogram bisect each other)
∠PAC = ∠QCA (AB ‖ DC, alternate angles)
So, by ASA congruence rule, we have
ΔPOA ≅ ΔQOC
Area (ΔPOA) = Area (ΔQOC)
Hence, proved
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