Answer :

Given that,

ABCD is a parallelogram


To prove: (i) Area () = Area ()


(ii) Area () = Area ()


Proof: We know that,


Diagonals of a parallelogram bisect each other


Therefore,


AO = OC and,


BO = OD



(i) In ΔDAC, DO is a median.


Therefore,


Area (ΔADO) = Area (ΔCDO)


Hence, proved


(ii) In , since BO is a median


Then,


Area (ΔBAO) = Area (ΔBCO) (i)


In a ΔPAC, since PO is the median


Then,


Area (ΔPAO) = Area (ΔPCO) (ii)


Subtract (ii) from (i), we get


Area (ΔBAO) - Area (ΔPAO) = Area (ΔBCO) - Area (ΔPCO)


Area (ΔABP) = Area (ΔCBP)


Hence, proved


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