Answer :
Construction: Draw DN⊥ AB and PM⊥ AB.
Proof: Area of parallelogram ABCD = AB * DN
Area (Δ APB) = 
(AB * PM)
= AB * PM < AB * DN
= 
(AB * PM) < 
(AB * DN)
= Area (Δ APB) < 
Area of parallelogram ABCD
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