Answer :
Given that,
DC = 17 cm
AD = 9 cm
And,
BC = 8 cm
In Δ BCD, we have
CD2 = BD2 + BC2
(17)2 = BD2 + (8)2
BD2 = 289 – 64
=15
In Δ ABD, we have
BD2 = AB2 + AD2
(15)2 = AB2 + (9)2
AB2 = 225 – 81
= 144
=12
Therefore,
Area of Quadrilateral ABCD = Area (Δ ABD) + Area (Δ BCD)
Area of quadrilateral ABCD = 
(12 × 9) + 
(8 × 17)
= 54 + 68
= 112 cm2
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