Answer :

Given that,

DC = 17 cm


AD = 9 cm


And,


BC = 8 cm


In Δ BCD, we have


CD2 = BD2 + BC2


(17)2 = BD2 + (8)2


BD2 = 289 – 64


=15


In Δ ABD, we have


BD2 = AB2 + AD2


(15)2 = AB2 + (9)2


AB2 = 225 – 81


= 144


=12


Therefore,


Area of Quadrilateral ABCD = Area (Δ ABD) + Area (Δ BCD)


Area of quadrilateral ABCD = (12 × 9) + (8 × 17)


= 54 + 68


= 112 cm2


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Division of PolynomialsDivision of PolynomialsDivision of Polynomials46 mins
Newton's Second LawNewton's Second LawNewton's Second Law46 mins
R D Sharma | Surface Area and VolumesR D Sharma | Surface Area and VolumesR D Sharma | Surface Area and Volumes39 mins
Surface Area and Volume of Right Circular ConeSurface Area and Volume of Right Circular ConeSurface Area and Volume of Right Circular Cone37 mins
Final Phase & Legacy of the RevolutionFinal Phase & Legacy of the RevolutionFinal Phase & Legacy of the Revolution43 mins
Newton's Third LawNewton's Third LawNewton's Third Law44 mins
Miscellaneous questionsMiscellaneous questionsMiscellaneous questions42 mins
Smart Revision | Surface Areas and Volume of SolidsSmart Revision | Surface Areas and Volume of SolidsSmart Revision | Surface Areas and Volume of Solids31 mins
Significance of Newton's Laws in daily lifeSignificance of Newton's Laws in daily lifeSignificance of Newton's Laws in daily life42 mins
Newton's First LawNewton's First LawNewton's First Law45 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses