Answer :

Given 3x – 1 ≥ 5 and x + 2 > –1


Let us consider the first inequality.


3x – 1 ≥ 5


3x – 1 + 1 ≥ 5 + 1


3x ≥ 6



x ≥ 2


x (2, ∞) (1)


Now, let us consider the second inequality.


x + 2 > –1


x + 2 – 2 > –1 – 2


x > –3


x (–3, ∞) (2)


From (1) and (2), we get


x (2, ∞) (–3, ∞)


x (2, ∞)


Thus, the solution of the given system of inequations is (2, ∞).


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