Answer :


Given: Radius of the circle = 3.5 cm and angle subtended by the arc = 90°


Area of the segment BDC = area of sector ABDC – area of triangle ABC


We know that the area of the minor sector


Area of ABDC


Area of ABDC = 9.625cm2


In ∆ABC,


A = 90°, AB = AC = 3.5 cm {radius of the circle}


∆ABC is a right angled triangle.


Area of ∆ABC


Area of ∆ABC


Area of ∆ABC = 6.125cm2


Area of the segment BDC = area of sector ABDC – area of triangle ABC


Area of the segment BDC = 9.625 – 6.125


Area of the segment BDC = 3.5cm2


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