# A chord of a circ

Given: Radius of the circle = 3.5 cm and angle subtended by the arc = 90°

Area of the segment BDC = area of sector ABDC – area of triangle ABC

We know that the area of the minor sector

Area of ABDC

Area of ABDC = 9.625cm2

In ∆ABC,

A = 90°, AB = AC = 3.5 cm {radius of the circle}

∆ABC is a right angled triangle.

Area of ∆ABC

Area of ∆ABC

Area of ∆ABC = 6.125cm2

Area of the segment BDC = area of sector ABDC – area of triangle ABC

Area of the segment BDC = 9.625 – 6.125

Area of the segment BDC = 3.5cm2

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