Answer :

Given 2x + 6 ≥ 0 and 4x – 7 < 0


Let us consider the first inequality.


2x + 6 ≥ 0


2x + 6 – 6 ≥ 0 – 6


2x ≥ –6



x ≥ –3


x [–3, ∞) (1)


Now, let us consider the second inequality.


4x – 7 < 0


4x – 7 + 7 < 0 + 7


4x < 7




(2)


From (1) and (2), we get




Thus, the solution of the given system of inequations is


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