Answer :

Given that,

Area of parallelogram ABCD = 124 cm^{2}

Construction: Draw AP perpendicular to DC

Proof: Area of parallelogram AFED = DF * AP (i)

Area of parallelogram EBCF = FC * AP (ii)

And,

DF = FC (iii) (F is the mid-point of DC)

Compare (i), (ii) and (iii), we get

Area of parallelogram AEFD = Area of parallelogram EBCF

Therefore,

Area of parallelogram AEFD =

= = 62 cm^{2}

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