# In a trapezium AB

Consider a trapezium ABCD, it is given that

AB||CD and the AD is not parallel to BC.

From the figure, we can say the similarities of ΔABC and ΔADC.

AC = AC (Common side)

A = C (Alternate angles on opposite sides of traversal line are equal)

B≠D (One angle is obtuse and other is acute)

AB≠CD (From the figure)

From the above conclusions, we can say that any of the property like SSS, SAS, ASA is not satisfied. So, we can conclude that,

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