Q. 23.8( 24 Votes )

# In a trapezium AB

Answer :

Consider a trapezium **ABCD**, it is given that

**AB||CD** and the **AD** is not parallel to **BC**.

From the figure, we can say the similarities of **ΔABC** and **ΔADC**.

⇒ **AC = AC** (Common side)

⇒ **∠****A =** **∠****C** (Alternate angles on opposite sides of traversal line are equal)

⇒ **∠****B≠****∠****D** (One angle is obtuse and other is acute)

⇒ **AB≠CD** (From the figure)

From the above conclusions, we can say that any of the property like **SSS, SAS, ASA** is not satisfied. So, we can conclude that,

**ΔABC is not congruent toΔADC**.

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