Answer :

Given x + 3 < 0 and 2x < 14


Let us consider the first inequality.


x + 3 < 0


x + 3 – 3 < 0 – 3


x < –3


x ( –∞, –3) (1)


Now, let us consider the second inequality.


2x < 14



x < 7


x (–∞, 7) (2)


From (1) and (2), we get


x (–∞, –3) (–∞, 7)


x ( –∞, –3)


Thus, the solution of the given system of inequations is (–∞, –3).


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