Solve the followi

Given

For this inequation to be true, there are two possible cases.

i. 25x + 17 > 0 and 8x + 3 < 0

⇒ 25x + 17 – 17 > 0 – 17 and 8x + 3 – 3 < 0 – 3

⇒ 25x > –17 and 8x < –3

However,

Hence,

ii. 25x + 17 < 0 and 8x + 3 > 0

⇒ 25x + 17 – 17 < 0 – 17 and 8x + 3 – 3 > 0 – 3

⇒ 25x < –17 and 8x > –3

However,

Hence, this case is not possible.

Thus, the solution of the given inequation is.