Q. 273.8( 4 Votes )

Solve the followi

Answer :

Given









For this inequation to be true, there are two possible cases.


i. 25x + 17 > 0 and 8x + 3 < 0


25x + 17 – 17 > 0 – 17 and 8x + 3 – 3 < 0 – 3


25x > –17 and 8x < –3




However,


Hence,


ii. 25x + 17 < 0 and 8x + 3 > 0


25x + 17 – 17 < 0 – 17 and 8x + 3 – 3 > 0 – 3


25x < –17 and 8x > –3




However,


Hence, this case is not possible.


Thus, the solution of the given inequation is.


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