Q. 264.2( 5 Votes )

Solve the followi

Answer :

Given









For this inequation to be true, there are two possible cases.


i. x + 7 > 0 and x + 3 < 0


x + 7 – 7 > 0 – 7 and x + 3 – 3 < 0 – 3


x > –7 and x < –3


x (–7, ∞) (–∞, –3)


However, (–7, ∞) (–∞, –3) = (–7, –3)


Hence, x (–7, –3)


ii. x + 7 < 0 and x + 3 > 0


x + 7 – 7 < 0 – 7 and x + 3 – 3 > 0 – 3


x < –7 and x > –3


x (–∞, –7) (–3, ∞)


However, (–∞, –7) (–3, ∞) =


Hence, this case is not possible.


Thus, the solution of the given inequation is (–7, –3).


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