Q. 264.2( 5 Votes )

# Solve the followi

Answer :

Given        For this inequation to be true, there are two possible cases.

i. x + 7 > 0 and x + 3 < 0

x + 7 – 7 > 0 – 7 and x + 3 – 3 < 0 – 3

x > –7 and x < –3

x (–7, ∞) (–∞, –3)

However, (–7, ∞) (–∞, –3) = (–7, –3)

Hence, x (–7, –3)

ii. x + 7 < 0 and x + 3 > 0

x + 7 – 7 < 0 – 7 and x + 3 – 3 > 0 – 3

x < –7 and x > –3

x (–∞, –7) (–3, ∞)

However, (–∞, –7) (–3, ∞) =

Hence, this case is not possible.

Thus, the solution of the given inequation is (–7, –3).

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