Q. 245.0( 2 Votes )

Solve the followi

Answer :

Given









For this inequation to be true, there are two possible cases.


i. x – 3 > 0 and x + 6 < 0


x – 3 + 3 > 0 + 3 and x + 6 – 6 < 0 – 6


x > 3 and x < –6


x (3, ∞) (–∞, –6)


However, (3, ∞) (–∞, –6) =


Hence, this case is not possible.


ii. x – 3 < 0 and x + 6 > 0


x – 3 + 3 < 0 + 3 and x + 6 – 6 > 0 – 6


x < 3 and x > –6


x (–∞, 3) (–6, ∞)


However, (–∞, 3) (–6, ∞) = (–6, 3)


Hence, x (–6, 3)


Thus, the solution of the given inequation is (–6, 3).


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Solve each of theRD Sharma - Mathematics

Solve each of theRD Sharma - Mathematics

Solve each of theRD Sharma - Mathematics

Solve each of theRD Sharma - Mathematics

Solve each of theRD Sharma - Mathematics

Solve each of theRD Sharma - Mathematics

Solve each of theRD Sharma - Mathematics

Solve each of theRD Sharma - Mathematics

Solve each of theRD Sharma - Mathematics

Solve each of theRD Sharma - Mathematics