Q. 183.7( 3 Votes )

Solve the followi

Answer :

Given



3(x – 2) ≤ 5x + 8


3x – 6 ≤ 5x + 8


3x – 6 + 6 ≤ 5x + 8 + 6


3x ≤ 5x + 14


5x + 14 ≥ 3x


5x + 14 – 14 ≥ 3x – 14


5x ≥ 3x – 14


5x – 3x ≥ 3x – 14 – 3x


2x ≥ –14



x ≥ –7


Thus, the solution of the given inequation is [–7, ∞).


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