Q. 2 L5.0( 2 Votes )

# Solve the followi

2x2 – (3 + 7i)x + (9i – 3) = 0

Given 2x2 – (3 + 7i)x + (9i – 3) = 0

Recall that the roots of quadratic equation ax2 + bx + c = 0, where a ≠ 0, are given by

Here, a = 2, b = –(3 + 7i) and c = (9i – 3)

By substituting i2 = –1 in the above equation, we get

By substituting –1 = i2 in the above equation, we get

We can write 16 + 30i = 25 – 9 + 30i

16 + 30i = 25 + 9(–1) + 30i

16 + 30i = 25 + 9i2 + 30i [ i2 = –1]

16 + 30i = 52 + (3i)2 + 2(5)(3i)

16 + 30i = (5 + 3i)2 [ (a + b)2 = a2 + b2 + 2ab]

By using the result 16 + 30i = (5 + 3i)2, we get

[ i2 = –1]

Thus, the roots of the given equation are 3i and.

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