Q. 20

# Evaluate the foll

Answer :

To Find : Now, let 4x + 1 be written as 2(2x - 1) + 3 and split

Therefore , = = Now solving, Let = u dx = Thus, becomes Now , = = ) = = Now solving, Now, can be written as i.e, Here , let x - = y dx = dy

Therefore, can be written as Formula Used: = log |x + |+ C

Since is of the form with change in variable. = log |y + |+ C

= log |y + |+ C

Since , x - = y and dx = dy = log |(x - ) + |+C

Therefore, = log |x - + |+C

Hence , = + log |x - + |+C

Therefore , = + log |x - + |+C

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