Q. 19

# Evaluate the following integrals: To Find : Now, let x - 5 be written as (2x + 1) - and split

Therefore , = = Now solving, Let = u dx = Thus, becomes Now , = = ) = = Now solving, Now, can be written as i.e, Here , let x + = y dx = dy

Therefore, can be written as Formula Used: = log |x + |+ C

Since is of the form with change in variable. = log |y + |+ C

= log |y + |+ C

Since , x + = y and dx = dy = log |(x + ) + |+C

Therefore, = log |x + + |+C

Now , = - log |x + + |+C

Therefore , = - log |x + + |+C

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