Answer :

To Find :


Now, let x + 2 be written as (2x + 1) + and split


Therefore ,


=


=


Now solving,


Let = u dx =


Thus, becomes


Now , = = ) =


=


Now solving ,


Now, can be written as


i.e,


Here , let x + = y dx = dy


Therefore, can be written as


Formula Used: = log |x +|+ C


Since is of the form with change in variable.


= log |y +|+ C


= log |y +|+ C


Since , x + = y and dx = dy


= log |(x + ) +|+C


Therefore,


= log |x + +|+C


Hence ,


= + log |(x + )+|+C


Therefore , = + log |(x + )+|+C


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