Q. 63.9( 14 Votes )

The angles of a p

Answer :

The sum of interior angles of pentagon is


= (n – 2) × 180° [n is number of sides of polygon)]


= (5 – 2) X 180°


= 540°


x + (x + 20) + (x + 40) + (x + 60) + (x + 80) = 540


5x + 200 = 540


5x = 340


X = 340 / 5


= 68°


So, smallest angle of pentagon is 68°

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