Answer :

To find:


Formula Used:


1. sec2 x = 1 + tan2 x


2.


3. sin 2x = 2 sin x cos x


Rewriting the given equation,





Let y = sin ϕ


dy = cos ϕ dϕ


Substituting in the original equation,


… (1)


Using partial fraction,



4y – 1 = A (2y - 4) + B


Equating the coefficients of y,


4 = 2A


A = 2


Also, -1 = -4A + B


B = 7


Substituting in (1),




2 log |y2 – 4y + 5| + 7 tan-1(y – 2) + C


But y = sin ϕ


2 log |sin2ϕ – 4 sin ϕ + 5| + 7 tan-1(sin ϕ – 2) + C


Therefore,



Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USRD Sharma - Volume 2

<img width=Mathematics - Exemplar

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1

Evaluate thMathematics - Exemplar

Evaluate the follRD Sharma - Volume 1

Evaluate the follRD Sharma - Volume 1