Answer :

In frustum


(Slant height)2 = (difference in radii )2 + (height)2


(Slant height)2 = (R - r)2 + (height)2


(Slant height)2 = (7cm – 3cm)2 + (3 cm)2


(Slant height)2 = 16 cm2 + 9 cm2


(Slant height)2 = 25 cm2


Slant height = √ (25 cm2)


Slant height = 5 cm


CSA of frustum = π[R + r]l


= π[7cm + 3cm] × 5cm


= 50 π cm2

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

A shuttle cock usGujarat Board Mathematics

If the radii of aGujarat Board Mathematics

The radii of a frGujarat Board Mathematics

A fez, the headgeGujarat Board Mathematics

A container, openGujarat Board Mathematics

A bucket is in thGujarat Board Mathematics

A metal bucket isGujarat Board Mathematics