Answer :


Given.


Volume of frustum = 12308.8 cm3


Radii of frustum are 20cm and 12cm


Formula used/Theory.


CSA of frustum = π[R + r]l


Volume of frustum = h[R2 + r2 + Rr]


Volume of frustum = h[R2 + r2 + Rr]


= × h[(20cm)2 + (12cm)2 + 20cm × 12cm]


= × h[400cm2 + 144cm2 + 240cm2]


= × h × 784cm2


= × h × 22 × 112


= × 22 × 112 × h = 12308.8 cm3


h = = 15 cm


In frustum


(Slant height)2 = (difference in radii )2 + (height)2


(Slant height)2 = (R - r)2 + (height)2


(Slant height)2 = (20cm – 12cm)2 + (15 cm)2


(Slant height)2 = 64 cm2 + 225 cm2


(Slant height)2 = 289 cm2


Slant height = √ (289 cm2)


Slant height = 17 cm


CSA of cone = π[R + r]l


= [12cm + 20cm] × 17cm


= × 32cm × 17cm


= 1709.71 cm2


Rate of 1 cm2 = Rs. 10


Rate of 1709.71 cm2 = Rs. 10 × 1709.71


= Rs. 17097.1


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