Answer :

In the figure assume, A to be the point 40m away from the foot of the tower BC. Join A,B and A,C and A,D. Let DC be the water tank and BC be the tower. We get two right-angled triangles ABC and ABD, right angled at B. Also, BAC = 30° and BAD = 45°. We use trigonometric ratios tan using AB as base and BC as height(for ∆ABC) and AB as base and CD as height(for ∆ABD). Let BC be x.


In ∆ABC,


So, BC = 23.09m.

In ∆ABD,


i. Height of the tower = BC = 23.1m

ii. Depth of the tank = DC = 16.9m

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