Answer :

In the figure assume, A to be the point 40m away from the foot of the tower BC. Join A,B and A,C and A,D. Let DC be the water tank and BC be the tower. We get two right-angled triangles ABC and ABD, right angled at B. Also, BAC = 30° and BAD = 45°. We use trigonometric ratios tan using AB as base and BC as height(for ∆ABC) and AB as base and CD as height(for ∆ABD). Let BC be x.


Untitled3.jpg


In ∆ABC,



or,



So, BC = 23.09m.


In ∆ABD,



or,



i. Height of the tower = BC = 23.1m


ii. Depth of the tank = DC = 16.9m


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses