Answer :


In the given figure, let AB be the tower. Let P and C be the points on the ground 4 m and 9 m from the foot of the tower. Join B, P and C. So, BC = 9m, BP = 4m. Again join P and C with A. Then we get two right-angled triangles ABP and ABC with right angle at B. Also, APB and ACB are given to be complementary. So, APB + ACB = 90°. We have to show that the height of the tower is 6 m.
We find the value of AB from ∆ABC using tan and also using the fact that tan(90-θ) = cotθ.

In ∆ABC,


We will now use the above-found value of AB in ∆APB.

From ∆APB,





Hence, proved.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses