Answer :

Untitled20.jpg


In the above figure, let B be the position of the man and AE be the cliff. We are given that the position of the man is 16 m above water level. Draw a line BD to a point D on the water level. So, BD = 16 m. Now, we are given that the angle of elevation of the top of the tower from the position of the man is 60°. Join A and B. Also, draw a line BC on to the line AE parallel to the water level. Then we get a right angled triangle ABC with right angle at B and ABC = 60°. Also, the angle of depression of the bottom of the tower from the position of the man is 30°. So, CBE = 30°. Joining B and E we get a right angled triangle BDE. And, BED = CBE = 30°. We need to find the distance of the ship from the cliff, that is DE and the height of the cliff AE.


We first find DE from the ∆BDE by using the trigonometric ratio tan.


In ∆BDE,



or,



or,



Now, BC = DE = 16√3 m.


From ∆ABC,



or,



or,



Also, CE = BD = 16 m.


Hence, the height of the cliff is AE = AC + CE = 48 + 16 = 64 m.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses