Q. 24.3( 242 Votes )
During the medical check-up of 35 students of a class, their weights were recorded as follows:

Draw a less than type ogive for the given data. Hence obtain the median weight from the graph and verify the result by using the formula
Answer :
The frequency distribution table of less than type graph is as follows:
Now,
Taking upper class interval on x-axis and their respective frequencies on y-axis, ogive will be:
Here, N = 35
Mark the point A whose ordinate is 17.5 and is x-ordinate is 46.5.
Hence,
Median of the data is 46.5
Now,
It can be observed that the difference between two consecutive upper class limits is 2
The class marks with respective frequencies are obtained below:

We can see that the cumulative frequency is greater than n/2 and is 28 which belongs to the interval 46-48
Hence,
Median class = 46-48
Lower limit, l = 46
cf = 14
f = 14
h = 2
Now,
Median can be calculated as:
= 46.5
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PREVIOUSThe following distribution gives the daily income of 50 workers of a factoryConvert the distribution above to a less than type cumulative frequency distribution, and draw its ogiveNEXTThe following table gives production yield per hectare of wheat of 100 farms of a village
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