# BM and CN are per

draw LS perpendicular to line MN

the line BM , LS,CN being the same perpendiculars , on line MN are parallel to each other

We have , BL=LC (L is mid point of BC)

Using intercept theorem,

MS = SN………………(i)

Now in ∆MLS and ∆LSN

MS=SN

LSM=LSN = 90° ( LS perpendicular to MN) and SL=LS is common

∆MLS ∆LSN (SAS congruency )

LM= LN proved

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