Q. 16

# The angles of a q

Answer :

Let the smallest term be x, and the largest term be 2x

Then AP formed= x, ?, ?, 2x

so,  360°= 4/2 [x+ 2x]....[We know that a+(n-1) d= last term= 2x]

180°= 3x

x= 60°

Now, 60° is least angle.

= 60°= π/180° × 60°

60° = π/3 rad

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