Answer :

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Let AD and BC be the two poles of equal height standing on the two sides of the road of width 80 m. Join DC. Then DC = 80 m. P is a point on the road from which the angle of elevation of the top of tower AD is 60°. Also, the angle of depression of the point P from the point B is 30°. Draw a line BX from B parallel to the ground. Then XBP = BPC = 30°. We are to find the height of the poles and the distance of the point P from both the poles. Also, APD = 60°.


Let DP = x. Then PC = 80-x.


In ∆APD,



or,



Now, from ∆APD,



or,



Now, BC = AD


So,



or,



or,


x = 20 m


So,PD = 20 m. Hence, PC = 80-20 = 60 m. Also, BC = AD = 20√3 m.


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