Answer :
Let AD and BC be the two poles of equal height standing on the two sides of the road of width 80 m. Join DC. Then DC = 80 m. P is a point on the road from which the angle of elevation of the top of tower AD is 60°. Also, the angle of depression of the point P from the point B is 30°. Draw a line BX from B parallel to the ground. Then ∠XBP = ∠BPC = 30°. We are to find the height of the poles and the distance of the point P from both the poles. Also, ∠APD = 60°.
Let DP = x. Then PC = 80-x.
In ∆APD,
or,
Now, from ∆APD,
or,
Now, BC = AD
So,
or,
or,
x = 20 m
So,PD = 20 m. Hence, PC = 80-20 = 60 m. Also, BC = AD = 20√3 m.
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