In a circle of di

Diameter = 30 cm

Length of chord = 15 cm

Radius = 15 cm [ r = 0.5 x diameter ]

Since the radius is equal to the length of the chord

Hence the formed triangle in the circle is an equilateral triangle.

θ = 60°

We know that l = r × θ

l = = 5 x 3.14 = 15.7

Therefore, the length of the minor arc is 15.7 cm