Answer :
Given,
ABCD is a rectangle
∠ABD = 40∘
∠ABD + ∠DBC = 90∘ (angles of rectangle)
∠DBC = 90∘ – 40∘ = 50∘
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Quiz | Properties of Parallelogram31 mins
Extras on Quadrilaterals40 mins
Critical Thinking Problems on Quadrilaterals44 mins
Smart Revision | Quadrilaterals43 mins
Quiz | Basics of Quadrilaterals36 mins
RD Sharma | Extra Qs. of Cyclic Quadrilaterals31 mins












Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
Fill in the blank
RD Sharma - MathematicsThe bisectors of
RD Sharma - MathematicsThe figure formed
RD Sharma - MathematicsThe figure formed
RD Sharma - MathematicsThe figure formed
RD Sharma - MathematicsThe two diagonals
RD Sharma - MathematicsPQRS is a quadril
RD Sharma - MathematicsTwo consecutive s
RD Sharma - MathematicsDiagonals necessa
RD Sharma - MathematicsThe opposite side
RD Sharma - Mathematics