Q. 27

If the coordinate

Let A(x1 , y1), B(x2 , y2) and C(x3 , y3) be the vertices of triangle.

Let D(3, -2), E(-3, 1) and F(4, -3) be the midpoints of sides BC, CA and AB respectively.

By midpoint formula.

x = , y =

For midpoint D(3, -2) of side BC,

3 = , -2 =

= 6 and = -4 …(1)

For midpoint E(-3, 1) of side CA,

-3 = , 1 =

= -6 and = 2 …(2)

For midpoint F(4, -3) of side AB,

4 = , -3 =

= 8 and =-6 …(3)

Adding 1,2 and 3, we get,

=6 -6 + 8

And = -4 + 2 -6

2(= 8 and 2() = -8

= 4 and = -4

+ 6 = 4 and – 4 = -4 …from 1

= -2 and = 0

Substituting above values in 3,

-2 + and 0 + = -6

= 10 and = -6

Similarly for equation 2,

-2 + = -6 and 0 + = 2

= -4 and = 2

Hence the vertices of triangle are A(-2 , 0), B(10 ,-6) and C(-4 ,2)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses