Q. 74.8( 6 Votes )

A tent of height 3.3 m is in the form of a right circular cylinder of diameter 12m and height 2.2m, surmounted by a right circular cone of the same diameter. Find the cost of the canvas of the tent at the rate of Rs. 500 per m2.

Answer :


Given: Height of the tent = 3.3 m


The height of the cylindrical portion = 2.2 m


The height of the conical portion


= Height of the tent – Height of the cylindrical portion


= 3.3 – 2.2


= 1.1m


Given Diameter of the cylinder, d = 12m



CSA of cylindrical portion = 2πrh



= 82.971 m2


Firstly, we have to find the slant height (l) of the conical portion


l2 = h2 + r2


l2 = (1.1)2 + (6)2


l2 = 1.21 + 36


l2 = 37.21


l = √37.21


l = 6.1m


CSA of the conical portion = πrl



= 115.029 m2


So,


Total Surface Area of the tent = Surface area of conical portion + surface Area of cylindrical portion


= 115.029 + 82.971


= 198 m2


Canvas required to make the tent = 198 m2


Cost of 1m2 canvas = Rs 500


Cost of 198 m2 canvas = Rs 500 × 198


= Rs 99000


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Surface Area and Volumes43 mins
Quiz | Surface Area and Volumes42 mins
Surface Area and Volume49 mins
Idioms and Phrases43 mins
Goprep Genius Quiz | Analogy and Classification48 mins
Acid - Types and Nomenclature52 mins
Combination and Decomposition Reactions59 mins
Resources and Development34 mins
Quiz | Acid: Types and Nomenclature50 mins
Mutations and Viruses49 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses