# A tent of height 3.3 m is in the form of a right circular cylinder of diameter 12m and height 2.2m, surmounted by a right circular cone of the same diameter. Find the cost of the canvas of the tent at the rate of Rs. 500 per m2.

Given: Height of the tent = 3.3 m

The height of the cylindrical portion = 2.2 m

The height of the conical portion

= Height of the tent – Height of the cylindrical portion

= 3.3 – 2.2

= 1.1m

Given Diameter of the cylinder, d = 12m

CSA of cylindrical portion = 2πrh

= 82.971 m2

Firstly, we have to find the slant height (l) of the conical portion

l2 = h2 + r2

l2 = (1.1)2 + (6)2

l2 = 1.21 + 36

l2 = 37.21

l = √37.21

l = 6.1m

CSA of the conical portion = πrl

= 115.029 m2

So,

Total Surface Area of the tent = Surface area of conical portion + surface Area of cylindrical portion

= 115.029 + 82.971

= 198 m2

Canvas required to make the tent = 198 m2

Cost of 1m2 canvas = Rs 500

Cost of 198 m2 canvas = Rs 500 × 198

= Rs 99000

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Surface Area and Volumes43 mins
Quiz | Surface Area and Volumes42 mins
Surface Area and Volume49 mins
Idioms and Phrases43 mins
Goprep Genius Quiz | Analogy and Classification48 mins
Acid - Types and Nomenclature52 mins
Combination and Decomposition Reactions59 mins
Resources and Development34 mins
Quiz | Acid: Types and Nomenclature50 mins
Mutations and Viruses49 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses