Q. 74.8( 6 Votes )

A tent of height 3.3 m is in the form of a right circular cylinder of diameter 12m and height 2.2m, surmounted by a right circular cone of the same diameter. Find the cost of the canvas of the tent at the rate of Rs. 500 per m2.

Answer :

Given: Height of the tent = 3.3 m

The height of the cylindrical portion = 2.2 m

The height of the conical portion

= Height of the tent – Height of the cylindrical portion

= 3.3 – 2.2

= 1.1m

Given Diameter of the cylinder, d = 12m

CSA of cylindrical portion = 2πrh

= 82.971 m2

Firstly, we have to find the slant height (l) of the conical portion

l2 = h2 + r2

l2 = (1.1)2 + (6)2

l2 = 1.21 + 36

l2 = 37.21

l = √37.21

l = 6.1m

CSA of the conical portion = πrl

= 115.029 m2


Total Surface Area of the tent = Surface area of conical portion + surface Area of cylindrical portion

= 115.029 + 82.971

= 198 m2

Canvas required to make the tent = 198 m2

Cost of 1m2 canvas = Rs 500

Cost of 198 m2 canvas = Rs 500 × 198

= Rs 99000

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