Answer :

Vertices of a quadrilateral are A (7, 10), B(-2, 5) and C(3, -4)


Using distance formula =


AB = = = units


BC = = = units


AC = = = units


Since AB = BC


Using Pythagoras theorem


AC2 = AB2 + BC2



212 = 106 + 106


212 = 212


Therefore vertices are of right isosceles triangle.


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