Q. 1 D5.0( 1 Vote )

# Solve the followi

6x2 – 17ix – 12 = 0

Given 6x2 – 17ix – 12 = 0

6x2 – 17ix – 12 × 1 = 0

We have i2 = –1 1 = –i2

By substituting 1 = –i2 in the above equation, we get

6x2 – 17ix – 12(–i2) = 0

6x2 – 17ix + 12i2 = 0

6x2 – 9ix – 8ix + 12i2 = 0

3x(2x – 3i) – 4i(2x – 3i) = 0

(2x – 3i)(3x – 4i) = 0

2x – 3i = 0 or 3x – 4i = 0

2x = 3i or 3x = 4i

Thus, the roots of the given equation are and.

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