Q. 9 B5.0( 1 Vote )

Using diffe

Let us assume that Also, let x = 0.008 so that x + Δx = 0.009

0.008 + Δx = 0.009

Δx = 0.001

On differentiating f(x) with respect to x, we get We know    When x = 0.008, we have      Recall that if y = f(x) and Δx is a small increment in x, then the corresponding increment in y, Δy = f(x + Δx) – f(x), is approximately given as Here, and Δx = 0.001

Δf = (8.3333)(0.001)

Δf = 0.0083333

Now, we have f(0.009) = f(0.008) + Δf  f(0.009) = 0.2 + 0.0083333

f(0.009) = 0.2083333

Thus, (0.009)1/3 ≈ 0.2083333

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