Answer :

Given x2 + x + 1 = 0




[ (a + b)2 = a2 + 2ab + b2]



We have i2 = –1 1 = –i2


By substituting 1 = –i2 in the above equation, we get





[ a2 – b2 = (a + b)(a – b)]





Thus, the roots of the given equation are.


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