Q. 53.9( 8 Votes )
Solve the following quadratic equations by factorization method
x2 + x + 1 = 0
Answer :
Given x2 + x + 1 = 0
[∵ (a + b)2 = a2 + 2ab + b2]
We have i2 = –1 ⇒ 1 = –i2
By substituting 1 = –i2 in the above equation, we get
[∵ a2 – b2 = (a + b)(a – b)]
Thus, the roots of the given equation are
.
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