Answer :

In the figure, we have two points marked, P = (-8, 3) and O1 = (9, 5)

According to question O1 is the origin for a different coordinate system, X1’O1X1 Y1’O1Y1.

For coordinates of P in the new system, we have to find the distance between O1and point P, measured FROM P.

By measuring distance on the graph above, we get

X1= -17 and Y1= -2

So, the coordinates of Point P in new system is (-17, -2)


Given, x= -8, y= 3

and a= 9, b=5 (Coordinates of O1)

As we know, x= a + x’

-8 = 9+ x’

x’ = -8-9

x’ = -17


y= b + y1

3 = 5+ y1

y1 = 3-5

y1 = -2

New coordinate, (x1, y1) are (-17,-2)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

Fill in the blankKarnataka Board - Mathematics Part II

True or false?<brKarnataka Board - Mathematics Part II

Suppose P has cooKarnataka Board - Mathematics Part II

Suppose you are gKarnataka Board - Mathematics Part II

A point P has cooKarnataka Board - Mathematics Part II

Match the followiKarnataka Board - Mathematics Part II

Suppose P is a poKarnataka Board - Mathematics Part II