Q. 34.0( 24 Votes )

In a quadrilateral ABCD, CO and DO are the bisectors of C and D respectively. Prove that COD = (A+B).

Answer :

Given,


In quadrilateral ABCD,


CO is the bisector of C


DO is the bisector of D


In ΔCOD



COD =


D+C = 360 – (A+B)


SO,


COD =


COD = (A+B) Proved.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Critical Thinking Problems on QuadrilateralsCritical Thinking Problems on QuadrilateralsCritical Thinking Problems on Quadrilaterals44 mins
Quiz | Properties of ParallelogramQuiz | Properties of ParallelogramQuiz | Properties of Parallelogram31 mins
Extras on QuadrilateralsExtras on QuadrilateralsExtras on Quadrilaterals40 mins
Smart Revision | QuadrilateralsSmart Revision | QuadrilateralsSmart Revision | Quadrilaterals43 mins
Quiz | Basics of QuadrilateralsQuiz | Basics of QuadrilateralsQuiz | Basics of Quadrilaterals36 mins
RD Sharma |  Extra Qs. of Cyclic QuadrilateralsRD Sharma |  Extra Qs. of Cyclic QuadrilateralsRD Sharma | Extra Qs. of Cyclic Quadrilaterals31 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses