Q. 34.0( 24 Votes )

# In a quadrilateral ABCD, CO and DO are the bisectors of ∠C and ∠D respectively. Prove that ∠COD = (∠A+∠B).

Answer :

Given,

In quadrilateral ABCD,

CO is the bisector of ∠C

DO is the bisector of ∠D

In ΔCOD

⇒ ∠COD =

⇒ ∠D+∠C = 360 – (∠A+∠B)

SO,

⇒ ∠COD =

⇒ ∠COD = (∠A+∠B) Proved.

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