Q. 255.0( 1 Vote )

# –x2 +

Given –x2 + x – 2 = 0

x2 – x + 2 = 0   [ (a – b)2 = a2 – 2ab + b2] We have i2 = –1 1 = –i2

By substituting 1 = –i2 in the above equation, we get    [ a2 – b2 = (a + b)(a – b)]   Thus, the roots of the given equation are .

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