Q. 165.0( 1 Vote )

# Solve the following quadratics

21x^{2} – 28x + 10 = 0

Answer :

Given 21x^{2} – 28x + 10 = 0

**Recall that the roots of quadratic equation ax ^{2} + bx + c = 0, where a ≠ 0, are given by**

Here, a = 21, b = –28 and c = 10

We have i^{2} = –1

By substituting –1 = i^{2} in the above equation, we get

Thus, the roots of the given equation are.

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