Q. 755.0( 2 Votes )
Choose the correct answer out of 4 options given against each Question
If f(x) = x100 + x99 + … x + 1, then f’(1) is equal to
A. 5050
B. 5049
C. 5051
D. 50051
Answer :
f(x)=x100 + x99 + ………….x + 1
f'(x) = 100x99 + 99x98 +…… + 1
f'(1) = 100(1)99 + 99(1)98 + …… + 1
[Using Arithmetic Progression, where d = -1, a = 100 & n = 100]
= 50 (200 – 99)
= 50 (101)
= 5050
Hence Option (A) is the correct answer.
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