Q. 55.0( 1 Vote )

# If <span lang="EN

Answer :

It is given that, Note:

I. Sum of first n natural numbers, 1 + 2 +3+…n, II. Sum of squares of first n natural numbers, 12 + 22 + 32+….n2, From the above identities, n2 + n = 420

n2 + n -420 = 0

(n – 20) (n + 21) = 0

n = 20 or -21

Since, n is the number of integers, n = 20 So, Rate this question :

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