Q. 33.6( 5 Votes )

# Find the sum 11<s

Answer :

It is required to find the sum 112 + 122 + 132+ …202

112 + 122 + 132+ …202 = Sum of squares of natural numbers starting from 1 to 20 – Sum of squares of natural numbers starting from 1 to 10.

Note:

Sum of squares of first n natural numbers, 12 + 22 + 32+….n2, From the above identities,

Sum of squares of natural numbers starting from 1 to 20 Sum of squares of natural numbers starting from 1 to 10 112 + 122 + 132+ …202= Sum of squares of natural numbers starting from 1 to 20 – Sum of squares of natural numbers starting from 1 to 10.

112 + 122 + 132+ …202 = 2870 – 385 = 2485

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