Q. 24.7( 3 Votes )

Find the sum (41 + 42 + 43 + …. + 100).

Answer :

It is required to find the sum (41 + 42 + 43 + …. + 100).


(41 + 42 + 43 + …. + 100) = Sum of integers starting from 1 to 100 – Sum of integers starting from 1 to 40.


Note:


Sum of first n natural numbers, 1 + 2 +3+…n,



From the above identities,


So, Sum of integers starting from 1 to 100




So, Sum of integers starting from 1 to 40




(41 + 42 + 43 + …. + 100) = Sum of integers starting from 1 to 100 – Sum of integers starting from 1 to 40.


(41 + 42 + 43 + …. + 100) = 5050 – 820 = 4230


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